Java Program to sort all the elements in an array in Ascending Order

This is a Java Program which arranges all the elements in an array in ascending order

Here initially first element in array and  its next element are compared array[0] and array[1] , if array[1] is greater then the values are swapped, and the process continues with 2 and 3 elements and son on until the end of array is reached.

Finally the obtained array is the sorted array in ascending order.

PROGRAM :

package codingcorner.in;

import java.util.Scanner;

public class AscendingOrder {
 public static void main(String[] args) {

  int i, j, no, temp;
  Scanner scan = new Scanner(System.in);
  System.out.print("\nEnter the number of Elements: \t");
  no = scan.nextInt();
  int arr[] = new int[no];
  for (i = 0; i < no; i++) {
   System.out.print("\nEnter Element" + (i + 1));
   arr[i] = scan.nextInt();
  }
  scan.close();
  for (i = 0; i < no; i++) {
   for (j = i; j < no; j++) {
    if (arr[i] > arr[j]) {
     temp = arr[i];
     arr[i] = arr[j];
     arr[j] = temp;
    }
   }
  }

  System.out.print("\nSorted array: ");
  for (i = 0; i < no; i++) {
   System.out.print("\t" + arr[i]);
  }
 }
}

OUTPUT :

Java - Sorting elements in an array in ascending order